Question

Помогите решить срочно Лыжник спускается с горы с начальной скоростью 6 м/с и ускорением 0,5 м/с2. Какова длина горы, если спуск с нее занял 12 с?

Answer 1

По формуле s=v0t + at^2/2 S= 6×12 + 0.5*144/2= 72 + 38.5= 110.5 метров

Answer 2

Calculating the Length of the Slope

To calculate the length of the slope, we can use the following kinematic equation:

v^2 = u^2 + 2as

Where: - v = final velocity - u = initial velocity - a = acceleration - s = distance

Given: - Initial velocity (u) = 6 m/s - Acceleration (a) = 0.5 m/s^2 - Time (t) = 12 s

We can use the equation to solve for the distance (s).

Calculation

Using the kinematic equation:

v = u + at

Where: - v = final velocity - u = initial velocity - a = acceleration - t = time

We can calculate the final velocity (v) using the given values.

v = u + at v = 6 m/s + (0.5 m/s^2 * 12 s) v = 6 m/s + 6 m/s v = 12 m/s

Now, we can use the calculated final velocity to find the distance (s).

v^2 = u^2 + 2as 12^2 = 6^2 + 2 * 0.5 * s 144 = 36 + s s = 144 - 36 s = 108 m

Answer

The length of the slope is 108 meters.