Question

в кабине подъемника лежит груз.если кабина рухается с постоянным поскорением,то вага груза большая на Р=2,0кН.когда кобина движется с постоянным поскорением,то вага груза большая на дельтаР=200Н.вызначыть модуль и напрамак поскорения кабины подъемника

Answer 1

1)  P=mg

m=p/g=2000Н/10=200кг

 

2) P=m(g+a)

g+a=P/m=2200/200=11

 

3) a= 11-g=11-10=1м/с*с

 

Answer 2

Lift Cabin Acceleration and Weight of the Load

When the lift cabin is moving with constant acceleration, the weight of the load experiences a change in both magnitude and direction. Let's calculate the module and direction of the acceleration of the lift cabin.

Given: - Weight of the load when the cabin is moving with constant velocity: R = 2.0 kN - Change in the weight of the load when the cabin is moving with constant acceleration: ΔR = 200 N

Calculating the Acceleration

To calculate the module and direction of the acceleration of the lift cabin, we can use the following equations:

1. When the cabin is moving with constant velocity, the weight of the load is given by: - R = m * g, where m is the mass of the load and g is the acceleration due to gravity.

2. When the cabin is moving with constant acceleration, the weight of the load changes to: - R + ΔR = m * (g + a), where a is the acceleration of the lift cabin.

By subtracting the first equation from the second, we get: - ΔR = m * a

Calculating the Module and Direction of the Acceleration

Using the given values, we can calculate the module and direction of the acceleration of the lift cabin: - ΔR = 200 N - m = R / g = 2.0 kN / 9.81 m/s^2 - g = 9.81 m/s^2 (acceleration due to gravity)

By substituting the values into the equation ΔR = m * a, we can solve for the acceleration (a).

Let's calculate the acceleration and its direction.