Question

Пуля вылетает из винтовки со скротью 800 м/с. Какова скорость винтовки при отдаче если масса винтовки в 400 раз больше массы пули.

Answer 1

Применяем закон сохранения импульса
m - масса пули, значит 400m - масса винтовки
0=mV1-400mV2
400mV2=mV1
сокращаем массы
400V2=800
V2=2

Answer 2

Calculating the Recoil Velocity of the Rifle

To calculate the recoil velocity of the rifle when a bullet is fired at a velocity of 800 m/s and the mass of the rifle is 400 times greater than the mass of the bullet, we can use the principle of conservation of momentum.

According to the principle of conservation of momentum, the momentum before the bullet is fired is equal to the momentum after the bullet is fired. The momentum of an object is given by the product of its mass and velocity.

Let's denote: - m1 as the mass of the bullet - V1 as the velocity of the bullet - m2 as the mass of the rifle - V2 as the velocity of the rifle after the bullet is fired

The equation for conservation of momentum can be written as: m1 * V1 = m2 * V2

Given: - m1 = mass of the bullet - V1 = velocity of the bullet = 800 m/s - m2 = 400 * m1 (mass of the rifle is 400 times greater than the mass of the bullet)

We can use the above equation to solve for V2, the velocity of the rifle after the bullet is fired.

Using the given information, we can calculate the recoil velocity of the rifle.

Calculations: m1 * V1 = m2 * V2 V2 = (m1 * V1) / m2 V2 = (m1 * 800) / (400 * m1) V2 = 800 / 400 V2 = 2 m/s

Therefore, the recoil velocity of the rifle when a bullet is fired at a velocity of 800 m/s and the mass of the rifle is 400 times greater than the mass of the bullet is 2 m/s.

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