Question

В калориметре смешали 0,39 кг воды при температуре 20 градусов и 0, 21кг воды при температуре 60 градусов найти общую температуру

Answer 1

Решение на фото, успехов :)

Answer 2

t=(0.39*4200*20+0.21*4200*60):0.6

Answer 3

Calculation of the Final Temperature

To find the final temperature when 0.39 kg of water at 20 degrees Celsius is mixed with 0.21 kg of water at 60 degrees Celsius, we can use the principle of conservation of energy. The total heat gained by the cooler water will be equal to the total heat lost by the hotter water.

Let's denote the final temperature as T.

The heat gained by the cooler water can be calculated using the formula:

Q1 = m1 * c * (T - T1)

Where: - Q1 is the heat gained by the cooler water - m1 is the mass of the cooler water (0.39 kg) - c is the specific heat capacity of water (approximately 4.18 J/g°C) - T1 is the initial temperature of the cooler water (20 degrees Celsius)

The heat lost by the hotter water can be calculated using the formula:

Q2 = m2 * c * (T2 - T)

Where: - Q2 is the heat lost by the hotter water - m2 is the mass of the hotter water (0.21 kg) - T2 is the initial temperature of the hotter water (60 degrees Celsius)

According to the principle of conservation of energy, Q1 = Q2. Therefore, we can equate the two equations:

m1 * c * (T - T1) = m2 * c * (T2 - T)

Now, let's solve this equation to find the value of T.

Calculation Steps

1. Substitute the given values into the equation: - m1 = 0.39 kg - c = 4.18 J/g°C - T1 = 20°C - m2 = 0.21 kg - T2 = 60°C

2. Convert the mass of water from grams to kilograms: - m1 = 0.39 kg * 1000 g/kg = 390 g - m2 = 0.21 kg * 1000 g/kg = 210 g

3. Substitute the values into the equation and solve for T:

390 g * 4.18 J/g°C * (T - 20°C) = 210 g * 4.18 J/g°C * (60°C - T)

Simplifying the equation:

1624.2 J * (T - 20) = 878.4 J * (60 - T)

Distributing and rearranging the equation:

1624.2 T - 32484 = 52704 - 878.4 T

Combining like terms:

2552.6 T = 85188.4

Solving for T:

T = 85188.4 / 2552.6 ≈ 33.36°C

Answer

The approximate final temperature when 0.39 kg of water at 20 degrees Celsius is mixed with 0.21 kg of water at 60 degrees Celsius is 33.36 degrees Celsius.