Question

помогите срочно!! 4) Луч падает на границу раздела сред воздух-жидкость под углом 45º и преломляется под углом 30º . Каков показатель преломления жидкости?

Answer 1

$n = \frac{sin \alpha }{sin \beta }$

sin α - угол падения ( 45° = sin 45° = 0,7 )
sin β - угол преломления ( 30° = sin 30° = 0,5 )

$n = \frac{0,7}{0,5}$ = 1,4 

Answer 2

Calculation of the Refractive Index of the Liquid

To calculate the refractive index of the liquid, we can use Snell's law, which relates the angles of incidence and refraction to the refractive indices of the two media involved. Snell's law is given by:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

Where: - n₁ is the refractive index of the first medium (air in this case), - θ₁ is the angle of incidence, - n₂ is the refractive index of the second medium (the liquid in this case), - θ₂ is the angle of refraction.

In this case, the angle of incidence is 45º and the angle of refraction is 30º. We need to find the refractive index of the liquid.

Let's substitute the given values into Snell's law and solve for n₂:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

1 * sin(45º) = n₂ * sin(30º)

Simplifying the equation:

sin(45º) = n₂ * sin(30º)

Taking the ratio of the sines:

n₂ = sin(45º) / sin(30º)

Using a calculator to evaluate the sines:

n₂ ≈ 1.414 / 0.5 ≈ 2.828

Therefore, the refractive index of the liquid is approximately 2.828.

Please note that the sources provided did not directly answer the question. However, the calculation of the refractive index is based on the well-known Snell's law, which is a fundamental principle in optics.