Question

2 медных шара массами 1m 4m нагревают. Оба шара получили одинаковое количество теплоты. Большой шар нагрелся на 5 градусов больше. На сколько градусов нагрелся маленький шар

Answer 1

Решение на фото, успехов :)

Answer 2

Problem Analysis

We have two copper spheres with masses of 1m and 4m, respectively. Both spheres receive the same amount of heat. The larger sphere is heated 5 degrees more than the smaller sphere. We need to determine the increase in temperature of the smaller sphere.

Solution

To solve this problem, we can use the principle of heat transfer, which states that the heat gained or lost by an object is equal to the product of its mass, specific heat capacity, and change in temperature.

Let's assume the specific heat capacity of copper is constant and denoted by c. The heat gained by the larger sphere can be calculated as:

Q1 = (mass of the larger sphere) x c x (change in temperature of the larger sphere)

Similarly, the heat gained by the smaller sphere can be calculated as:

Q2 = (mass of the smaller sphere) x c x (change in temperature of the smaller sphere)

Given that both spheres receive the same amount of heat, we can equate Q1 and Q2:

(mass of the larger sphere) x c x (change in temperature of the larger sphere) = (mass of the smaller sphere) x c x (change in temperature of the smaller sphere)

Since the specific heat capacity and the constant 'c' are the same for both spheres, we can cancel them out:

(mass of the larger sphere) x (change in temperature of the larger sphere) = (mass of the smaller sphere) x (change in temperature of the smaller sphere)

We are given that the change in temperature of the larger sphere is 5 degrees more than the change in temperature of the smaller sphere:

(mass of the larger sphere) x (change in temperature of the smaller sphere + 5) = (mass of the smaller sphere) x (change in temperature of the smaller sphere)

Now, we can solve this equation to find the change in temperature of the smaller sphere.

Let's substitute the mass of the larger sphere with 4m and the mass of the smaller sphere with 1m:

(4m) x (change in temperature of the smaller sphere + 5) = (1m) x (change in temperature of the smaller sphere)

Simplifying the equation:

4m x change in temperature of the smaller sphere + 20m = 1m x change in temperature of the smaller sphere

Rearranging the equation:

3m x change in temperature of the smaller sphere = -20m

Dividing both sides by 3m:

change in temperature of the smaller sphere = -20m / 3m

Therefore, the change in temperature of the smaller sphere is -20/3 degrees.

Answer

The smaller sphere is heated by -20/3 degrees.