Question

С каким ускорением падает тело массой 2 кг если сила сопротивления воздуха 12H ПОМОГИ ПОЖАЛУЙСТА

Answer 1

2 зн Ньютона
Ось вниз
ma=-Fc+mg
a= -Fc/m+g
a=-12/2+10=4м/с2
Ответ 4 м/с2

Answer 2

Calculating Acceleration Due to Air Resistance

To calculate the acceleration of an object falling with air resistance, we can use the following equation:

Acceleration = (Force of gravity - Force of air resistance) / Mass

Given: - Mass (m) = 2 kg - Force of air resistance = 12 N (assuming this is the force acting against the direction of motion)

Using the equation, we can calculate the acceleration.

Acceleration = (Force of gravity - Force of air resistance) / Mass

Acceleration = (9.81 m/s^2 - 12 N) / 2 kg

Acceleration ≈ (-2.19 m/s^2)

Therefore, the body with a mass of 2 kg falls with an acceleration of approximately -2.19 m/s^2 when the force of air resistance is 12 N.