Question

даю 46 баллов !!!!!!!!!!!!!!!!!!в электролитической ванне во время электролиза за 40 мин выделилось 3,96 г меди, определить мощность тока при котором происходил электролиз если сопротивление элекролитов 0,8 ом

Answer 1

0.8×40÷3.96. если не правильно то сори

Answer 2

Calculation of Current Power during Electrolysis

To determine the current power at which electrolysis occurred in the electrolytic bath, we can use the formula:

Power (P) = (Amount of Substance (m) / Time (t)) * Voltage (V)

Given: - Amount of substance (m) = 3.96 g - Time (t) = 40 min = 2400 s - Resistance of the electrolyte (R) = 0.8 Ω

To calculate the voltage (V), we can use Ohm's Law:

Voltage (V) = Current (I) * Resistance (R)

We need to find the current (I) at which the electrolysis occurred.

Let's calculate the voltage (V) first:

V = I * R

From the given resistance (R) of 0.8 Ω, we can calculate the voltage (V).

Now, let's calculate the current (I):

I = P / V

Substituting the values of power (P) and voltage (V) into the equation, we can find the current (I).

Finally, we can determine the power (P) at which the electrolysis occurred using the formula mentioned earlier.

Please note that the search results provided by You.com did not directly provide the necessary information to answer this question. Therefore, we will proceed with the calculations based on the given information and formulas.

Calculation Steps:

1. Calculate the voltage (V): - V = I * R

2. Calculate the current (I): - I = P / V

3. Calculate the power (P): - P = (m / t) * V

Let's proceed with the calculations.

Calculation:

1. Calculate the voltage (V): - V = I * R - V = I * 0.8 Ω

2. Calculate the current (I): - I = P / V

3. Calculate the power (P): - P = (3.96 g / 2400 s) * V

Since we don't have the value of voltage (V) or power (P), we cannot provide a specific answer to the question without this information. Please provide the value of either the voltage or the power to proceed with the calculation.