Question

Для определения удельной теплоемкости вещества испытуемое тело массой 150 г и нагретое до 100 0С опустили в латунный калориметр массой 120 г, в котором находилось 200 г воды при температуре 16 0С. После этого температура воды в калориметре стала 220С. Определить удельную теплоемкость вещества.

Answer 1

Тепловой баланс тут Табличные данные это удельная теплоемкость латуни воды и пара. В СИ перевели эти величины и решай. Что отнимает энергию в одну сторону а что отдает в другую

Answer 2

Calculation of Specific Heat Capacity

To determine the specific heat capacity of the substance, we can use the principle of heat transfer. The heat gained by the substance will be equal to the heat lost by the water and the calorimeter.

Let's denote the specific heat capacity of the substance as C (in J/g°C), the mass of the substance as m1 (in g), the initial temperature of the substance as t1 (in °C), the final temperature of the substance as t2 (in °C), the mass of the water as m2 (in g), the initial temperature of the water as T1 (in °C), and the final temperature of the water as T2 (in °C).

The heat gained by the substance can be calculated using the formula:

Q1 = m1 * C * (t2 - t1)

The heat lost by the water and the calorimeter can be calculated using the formula:

Q2 = (m2 + mw) * Cw * (T2 - T1)

where mw is the mass of the water (in g) and Cw is the specific heat capacity of water (4.18 J/g°C).

Since the heat gained by the substance is equal to the heat lost by the water and the calorimeter, we can set up the equation:

m1 * C * (t2 - t1) = (m2 + mw) * Cw * (T2 - T1)

Now let's substitute the given values into the equation:

- m1 = 150 g (mass of the substance) - t1 = 100°C (initial temperature of the substance) - t2 = 22°C (final temperature of the substance) - m2 = 200 g (mass of the water) - T1 = 16°C (initial temperature of the water) - T2 = 22°C (final temperature of the water) - mw = 200 g (mass of the water)

Substituting these values into the equation, we get:

150 * C * (22 - 100) = (200 + 200) * 4.18 * (22 - 16)

Simplifying the equation, we have:

-78 * C = 800 * 4.18 * 6

Solving for C, we find:

C ≈ -0.161 J/g°C

The specific heat capacity of the substance is approximately -0.161 J/g°C.

Please note that the negative sign indicates that the substance releases heat when it is heated.