Question

Определить объем тела находящегося в керосине если на него действует архимедова сила 0,3Н

Answer 1

Плотность керосина ρ=800 кг/м³
Vт =F/ρg 
Vт = 0, 3 Н :(10 н/Кг *800 кг/м³) =0,04 *10⁻³ м³

Answer 2

Calculating the Volume of the Object in Kerosene

To determine the volume of the object in kerosene, we can use the formula for the buoyant force, which is given by the equation:

F = V * ρ * g,

where: - F is the buoyant force, - V is the volume of the object submerged in the fluid, - ρ is the density of the fluid (kerosene in this case), and - g is the acceleration due to gravity.

Given that the buoyant force acting on the object is 0.3 N, we can use this information to calculate the volume of the object in kerosene.

Calculation Steps

1. Calculate the Volume (V): - The formula for the buoyant force can be rearranged to solve for the volume: V = F / (ρ * g).

2. Substitute the Given Values: - The density of kerosene is approximately 0.8 g/cm³ or 800 kg/m³. - The acceleration due to gravity, g, is approximately 9.8 m/s².

3. Perform the Calculation: - Substitute the values into the formula and calculate the volume.

Calculation

Using the given values: - F = 0.3 N - ρ = 800 kg/m³ - g = 9.8 m/s²

We can calculate the volume using the formula: V = F / (ρ * g).

Substituting the values: V = 0.3 / (800 * 9.8).

Performing the calculation: V ≈ 3.06 x 10^-5 m³.

Therefore, the volume of the object in kerosene is approximately 3.06 x 10^-5 cubic meters.