Question

Льдина имеет объём 200 м3 плавает в реке.Найти объём её подводной части.номер 2)Найти F выт действующую на тело объёмом 50 дм3 помещённое в керосин.ПРОШУ РЕШИТЕ!СРОЧНООО:*Нужно полностью решение!

Answer 1

1)
V - объём льдины, V₁ - объём подводной части
p₁ - плотность льда, p₂ - плотность воды
mg = Vp₁g = Fa = V₁p₂g => V₁ = V(p₁/p₂) =0,9V поскольку я помню плотности.

2) F = pgV, p = 800 кг/м3 помойму, переведите объём в метры кубические  и вычислите.

Answer 2

Problem 1: Finding the volume of the underwater part of an iceberg

To find the volume of the underwater part of an iceberg, we need to know the density of ice and the density of water. The density of ice is approximately 917 kg/m³, and the density of water is approximately 1000 kg/m³.

Given: - Volume of the iceberg = 200 m³

To find the volume of the underwater part, we can use the principle of buoyancy. The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

The weight of the fluid displaced by the iceberg is equal to the weight of the iceberg itself. We can calculate the weight of the iceberg using the formula:

Weight = Density × Volume × g

Where: - Density is the density of the fluid (water) = 1000 kg/m³ - Volume is the volume of the iceberg = 200 m³ - g is the acceleration due to gravity = 9.8 m/s²

Now, let's calculate the weight of the iceberg:

Weight = 1000 kg/m³ × 200 m³ × 9.8 m/s²

Using the given values, we can calculate the weight of the iceberg.

Calculation:

Weight = 1000 kg/m³ × 200 m³ × 9.8 m/s²

Weight = 1960000 N

The weight of the iceberg is 1960000 Newtons.

Since the weight of the fluid displaced by the iceberg is equal to the buoyant force, we can calculate the volume of the underwater part of the iceberg using the formula:

Volume of underwater part = Weight of iceberg / Density of water

Substituting the values, we get:

Volume of underwater part = 1960000 N / 1000 kg/m³

Calculation:

Volume of underwater part = 1960000 N / 1000 kg/m³

Volume of underwater part = 1960 m³

Therefore, the volume of the underwater part of the iceberg is 1960 m³.

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