Question

Пуля пробила стену толщиной 20 см, скорость перед стенкой была 600 м/с а после стенки 300 м/с . С каким ускорением двигалась пуля внутри стенки

Answer 1

S=(u^2-v^2)/(2a)
2a=(u^2-v^2)/S
a=(u^2-v^2)/(2S)=(300^2-600^2)/(2*0,2) м/с^2 = -675000 м/с^2 = -675 км/с^2 !!!
знак минус, потому что происходит снижение скорости

Answer 2

Calculation of Acceleration Inside the Wall

To calculate the acceleration of the bullet inside the wall, we can use the equation of motion:

v^2 = u^2 + 2as

Where: - v is the final velocity of the bullet inside the wall (300 m/s) - u is the initial velocity of the bullet before hitting the wall (600 m/s) - a is the acceleration of the bullet inside the wall - s is the distance traveled by the bullet inside the wall (which is the thickness of the wall, 20 cm or 0.2 m)

Rearranging the equation, we get:

a = (v^2 - u^2) / (2s)

Substituting the given values, we can calculate the acceleration:

a = (300^2 - 600^2) / (2 * 0.2)

Calculating this expression gives us an acceleration of approximately -450,000 m/s^2.

Please note that the negative sign indicates that the acceleration is in the opposite direction of the initial velocity of the bullet.