
Из двух городов В и С, расстояние между которыми 540 км, одновременно навстречу друг другу выехали
два мотоциклиста, со скоростями 54 и 72 км\ч. Через сколько времени и на каком расстоянии от города С они встретятся?

Ответы на вопрос

54+48=102км/ч-общяя скорость
1вопрос)510:102=5ч
2вопрос)102•3=306км
ответ:5часов;306км



Problem Analysis
We are given two cities, V and S, with a distance of 540 km between them. Two motorcyclists start simultaneously from each city and travel towards each other. The first motorcyclist has a speed of 54 km/h, while the second motorcyclist has a speed of 72 km/h. We need to determine the time it takes for them to meet and at what distance from city S they will meet.
Solution
To solve this problem, we can use the formula:
Time = Distance / Speed
Let's calculate the time it takes for the motorcyclists to meet:
For the first motorcyclist: Time1 = Distance / Speed1 = 540 km / 54 km/h = 10 hours
For the second motorcyclist: Time2 = Distance / Speed2 = 540 km / 72 km/h = 7.5 hours
Since they start simultaneously, the time it takes for them to meet is the same for both motorcyclists. Therefore, they will meet after 7.5 hours.
To calculate the distance from city S where they will meet, we can use the formula:
Distance = Speed * Time
For the first motorcyclist: Distance1 = Speed1 * Time = 54 km/h * 7.5 hours = 405 km
For the second motorcyclist: Distance2 = Speed2 * Time = 72 km/h * 7.5 hours = 540 km
Therefore, they will meet at a distance of 405 km from city S.
Answer
The two motorcyclists will meet after 7.5 hours of traveling, at a distance of 405 km from city S.


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