Question

Неужели так сложно решить задачу? Пожалуйста, срочно решите задачу, УМОЛЯЮ, боже мой ‍♂️ Задача 3831. Электрическая схема состоит из пяти последовательно соединённых блоков. Вероятность безотказной работы каждого блока составляет 0.3, 0.5, 0.8, 0.1, 0.2.Считая выходы из строя различных блоков независимыми событиями, найти надёжность всей схемы в целом.

Answer 1

0.3+0.5+0.8+0.1+0.2=1.9

Answer 2

Problem Analysis

To find the reliability of the entire circuit, we need to calculate the probability that all five blocks work without failure. Each block has a different reliability probability, and we assume that the failures of different blocks are independent events.

Solution

To find the reliability of the entire circuit, we can multiply the reliability probabilities of each block together. This is based on the assumption that the failures of different blocks are independent events.

The reliability probabilities of the five blocks are given as follows: - Block 1: 0.3 - Block 2: 0.5 - Block 3: 0.8 - Block 4: 0.1 - Block 5: 0.2

To find the reliability of the entire circuit, we multiply these probabilities together:

Reliability of the entire circuit = 0.3 * 0.5 * 0.8 * 0.1 * 0.2

Calculating this expression gives us the reliability of the entire circuit.

Let's calculate it:

Reliability of the entire circuit = 0.3 * 0.5 * 0.8 * 0.1 * 0.2 = 0.0024

Therefore, the reliability of the entire circuit is 0.0024.

Please note that this calculation assumes that the failures of different blocks are independent events. If there are any dependencies or interactions between the blocks, the calculation may be different.

I hope this helps! Let me know if you have any further questions.