Question

Налетов на пружинный буфер , вагон массой 16 т , двигавшийся со скоростью 0.6 м/с , остановился , сжав пружину на 8 см . найти общую жесткость пружин буфера !!

Answer 1

mv^2/2 = kx^2/2

k = mv^2/x^2 = 16000*0.36/ 0.0064 = 0.9 МН/м

Answer 2

Calculation of the Total Stiffness of the Spring Buffer

To find the total stiffness of the spring buffer, we need to use the formula:

k = (m * v^2) / (2 * x)

Where: - k is the total stiffness of the spring buffer, - m is the mass of the wagon (16 tons), - v is the velocity of the wagon (0.6 m/s), - x is the compression of the spring (8 cm).

Let's substitute the given values into the formula and calculate the total stiffness:

k = (16 tons * (0.6 m/s)^2) / (2 * 8 cm)

First, we need to convert the mass from tons to kilograms and the compression from centimeters to meters:

- 16 tons = 16,000 kg - 8 cm = 0.08 m

Now we can calculate the total stiffness:

k = (16,000 kg * (0.6 m/s)^2) / (2 * 0.08 m)

Simplifying the equation:

k = (16,000 kg * 0.36 m^2/s^2) / 0.16 m

k = 36,000 N/m

Therefore, the total stiffness of the spring buffer is 36,000 N/m.