Question

Тело, находящееся в 20 см от оси диска, улетело от него, когда скорость вращения диска стала 0,6 м/с. Найти коэффициент трения тела о диск. Можно дано и как можно больше объяснений

Answer 1

Дано
v=0.6 м/с
r= 20 см=0,2 м
--------------------
k=?

Тело оторвется от диска, когда центростремительная сила равная mv²/r и сила трения kmg где k коэффициент трения, равны между собой. Сокращая на  m  имеем kg=v²/r     k=v²/gr=0.6²/10*0.2=0.18

Answer 2

Calculation of the Coefficient of Friction

To find the coefficient of friction between the body and the disk, we can use the given information that the body flew off the disk when the rotational speed of the disk reached 0.6 m/s and the body was located 20 cm away from the axis of the disk.

The coefficient of friction can be calculated using the formula:

Coefficient of Friction (μ) = (Acceleration due to Centripetal Force) / (Acceleration due to Gravity)

To calculate the acceleration due to centripetal force, we need to find the centripetal acceleration of the body when it flew off the disk.

The centripetal acceleration can be calculated using the formula:

Centripetal Acceleration (a) = (Angular Velocity (ω))^2 * Distance from the Axis (r)

Given that the distance from the axis of the disk is 20 cm (0.2 m) and the angular velocity is 0.6 m/s, we can calculate the centripetal acceleration.

Centripetal Acceleration (a) = (0.6 m/s)^2 * 0.2 m

Now, we need to calculate the acceleration due to gravity, which is approximately 9.8 m/s^2.

Finally, we can calculate the coefficient of friction using the formula mentioned earlier.

Coefficient of Friction (μ) = (Centripetal Acceleration (a)) / (Acceleration due to Gravity)

Let's calculate the coefficient of friction using the given values:

Centripetal Acceleration (a) = (0.6 m/s)^2 * 0.2 m = 0.072 m/s^2

Coefficient of Friction (μ) = (0.072 m/s^2) / (9.8 m/s^2) = 0.00735

Therefore, the coefficient of friction between the body and the disk is approximately 0.00735.

Please note that the above calculation assumes that the body flew off the disk due to the centripetal force and friction between the body and the disk. Other factors, such as air resistance, are not considered in this calculation.