Question

Спутник земли находится на круговой орбите удалённой от поверхности земли на 300км определите скорость спутника и его период обращения если M=6*10^24кг R=6400кг.

Answer 1

V^2=GM/V^2=6,67*10^-11*6*10^24/6700*10^3=6*10^7(м/с)^2
V=7,74*10^3м/с
Т=2*3,14*6700*10^3/7,74*10^3=5436с=1,5 год

Answer 2

Calculation of Satellite Speed and Orbital Period

To determine the speed and orbital period of a satellite in a circular orbit around the Earth, we can use the following formulas:

1. Speed of the satellite: - The speed of a satellite in a circular orbit is given by the formula: v = √(GM/R), where v is the speed of the satellite, G is the gravitational constant, M is the mass of the Earth, and R is the distance between the center of the Earth and the satellite. - The mass of the Earth