Question

Игрушка массой 200 г двигаясь из состояния покоя проходит при равноускоренном движении путь 1м за время равное 4с определите равнодействующую сил действующих на нее

Answer 1

S=a*t*t/2=F*t*t/(2*M), откуда

F=2*M*s/(t*t)=2*0.2*1/(4*4)=0.4/16=0.025 Н

Answer 2

Не   Забудь   поставить    лучшее    решение)

Answer 3

Problem Analysis

We are given the following information: - The toy has a mass of 200 g. - It moves from a state of rest. - It travels a distance of 1 m. - The time taken to cover this distance is 4 s.

We need to determine the resultant force acting on the toy.

Solution

To find the resultant force acting on the toy, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

The acceleration can be calculated using the formula for uniformly accelerated motion:

\[S = ut + \frac{1}{2}at^2\]

where: - S is the distance traveled (1 m), - u is the initial velocity (0 m/s, as the toy starts from rest), - t is the time taken (4 s), and - a is the acceleration.

Rearranging the formula, we get:

\[a = \frac{2(S - ut)}{t^2}\]

Substituting the given values, we have:

\[a = \frac{2(1 - 0 \cdot 4)}{4^2}\]

Simplifying, we find:

\[a = \frac{2}{16} = \frac{1}{8} \, \text{m/s}^2\]

Now, we can calculate the resultant force using Newton's second law:

\[F = ma\]

Substituting the mass (200 g = 0.2 kg) and acceleration (\(\frac{1}{8}\) m/s²), we have:

\[F = 0.2 \cdot \frac{1}{8} = \frac{0.2}{8} = \frac{1}{40} \, \text{N}\]

Therefore, the resultant force acting on the toy is \(\frac{1}{40}\) N.

Answer

The resultant force acting on the toy is \(\frac{1}{40}\) N.