Question

ПЛИС ОЧЕНЬ НАДО МНЕ НАДО ЭТО СДЕЛАТЬ К 15 АПРЕЛЮплощадь большого поршня гидравлического пресса равна 200 сантиметров в квадрате на него действует сила 200 ньютона. какую силу нужно приложить к малому поршню площадью 10 сантиметров в квадрате,чтобы поршни оказались в равновесии???

Answer 1

F1*S1=F2*s2
S2=F1*S1/S2=200*200/10=4000 Н
Площади в м2 можно не переводить, так как в формуле есть отношение площадей!!!!

Answer 2

I can help you with your question.

According to Google Translate, your question is:

Answer in detail. PLEASE VERY NEED ME NEED TO DO THIS BY APRIL 15 The area of the large piston of the hydraulic press is equal to 200 square centimeters, a force of 200 newtons acts on it. what force needs to be applied to the small piston with an area of 10 square centimeters, so that the pistons are in equilibrium ???

This is a question about the principle of hydraulic press, which states that the pressure exerted by a fluid is the same at all points in the same level. Therefore, if we have two pistons connected by a fluid, the pressure on each piston is equal to the force divided by the area. That is, P = F / A.

To find the force on the small piston, we can use the formula:

F_small = P * A_small

Since the pressure is the same for both pistons, we can substitute P with F_large / A_large, where F_large and A_large are the force and area of the large piston. Therefore, we get:

F_small = (F_large / A_large) * A_small

Plugging in the given values, we get:

F_small = (200 N / 200 cm^2) * 10 cm^2

F_small = 10 N

So, the force that needs to be applied to the small piston is 10 newtons.

I hope this helps you understand the problem. If you need more help, you can check out this [link](https://online-otvet.ru/fizika/5cea739796f4e19a29f8c276) that explains the solution in Russian. Good luck with your assignment!