Question

Какое количество теплоты выделится при охлаждении 5 кг воды от тепературы 10 градусов до температуры 0 градусов и ее дальнейшем превращении в лед?

Answer 1

Q=cm(t2-t1)
Q= 4200×5(10−0)
Q=210000 Дж

Answer 2

Calculation of Heat Released during Cooling and Freezing of Water

To calculate the amount of heat released during the cooling and freezing of water, we need to consider two processes: cooling the water from 10 degrees Celsius to 0 degrees Celsius and then freezing it.

1. Cooling the water from 10 degrees Celsius to 0 degrees Celsius: - The specific heat capacity of water is approximately 4.18 J/g°C. - The mass of water is given as 5 kg. - The temperature change is from 10 degrees Celsius to 0 degrees Celsius, which is a decrease of 10 degrees. - Using the formula Q = m * c * ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, we can calculate the heat released during this process.

Calculation: - Q = 5 kg * 4.18 J/g°C * 10°C = 2090 J/g * 10°C = 20,900 J

2. Freezing the water: - The latent heat of fusion for water is approximately 334 J/g. - The mass of water is given as 5 kg. - To freeze the water, we need to convert it from liquid to solid form, which requires the release of latent heat.

Calculation: - Q = 5 kg * 334 J/g = 1670 J/g * 1000 g = 1,670,000 J

Total Heat Released during Cooling and Freezing of Water

To find the total heat released during the cooling and freezing of water, we need to add the heat released during the cooling process and the heat released during the freezing process.

Total Heat Released = Heat Released during Cooling + Heat Released during Freezing = 20,900 J + 1,670,000 J = 1,690,900 J

Therefore, the total amount of heat released during the cooling of 5 kg of water from 10 degrees Celsius to 0 degrees Celsius and its subsequent freezing into ice is approximately 1,690,900 J.

Please note that this calculation assumes ideal conditions and does not account for any heat loss to the surroundings.