Question

Помогите с физикой!Человек массой 70 кг прыгнул с высокого берега в море. Чему равна скорость движения человека через 0,5 сек после прыжка? Влияние сопротивления воздуха не учитывайте, силу тяжести, действующую на человека, примите равной 700 Н.

Answer 1

mv+MV=mv1+MV1(закон сохр.импульса)

в нашем случае

mv=(m+M)V

V=mv/(m+M)=70*6/(70+35)=4м/с

Ответ: 4м/с

Answer 2

Calculation of the Person's Velocity

To calculate the velocity of the person 0.5 seconds after jumping from a high cliff into the sea, we can use the principles of free fall. In this case, we can neglect the influence of air resistance and consider only the force of gravity acting on the person, which we will assume to be 700 N.

The equation for calculating velocity in free fall is:

v = gt

Where: - v is the velocity - g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth) - t is the time

In this case, the time is 0.5 seconds. Substituting the values into the equation, we can calculate the velocity:

v = (9.8 m/s^2) * (0.5 s) = 4.9 m/s

Therefore, the velocity of the person 0.5 seconds after jumping is 4.9 m/s.

Please note that this calculation assumes that the person jumps vertically downward and that there are no other external forces acting on the person during the jump.