Question

Пуля , выпущенная вертикально вверх из автомата АК-47, имеет начальную скорость 900м/с.Определите максимальную высоту, на которую оно поднимется.Начальное положение пули принять равным нулю.__________________________________________________Помогите в решении, пожалуйста!!!

Answer 1

Дано Vo=900 м/с Ho=0
Hmax - ?

Hmax= Vo²/2*g=900*900/2*10=40500 м

при условии что Fсопр=0

Answer 2

Calculation of Maximum Height Reached by a Bullet Fired Vertically Upwards

To determine the maximum height reached by a bullet fired vertically upwards from an AK-47 rifle with an initial velocity of 900 m/s, we can use the principles of projectile motion.

In this case, the bullet is subject to the force of gravity, which acts to slow it down as it moves upwards. At the highest point of its trajectory, the bullet momentarily comes to a stop before falling back down.

To find the maximum height, we can use the following equation:

v^2 = u^2 - 2as

Where: - v is the final velocity (which is 0 at the highest point) - u is the initial velocity (900 m/s) - a is the acceleration due to gravity (-9.8 m/s^2, assuming no air resistance) - s is the displacement (the maximum height we want to find)

Rearranging the equation, we have:

s = (u^2) / (2a)

Substituting the given values, we can calculate the maximum height reached by the bullet:

s = (900^2) / (2 * (-9.8))

Let's calculate the value:

s = (900^2) / (2 * (-9.8))