Question

Мяч бросают горизонтально с высоты 20 м с начальной скоростью 25 м/с. Найдите дальность полета.

Answer 1

1)h=gt^2/2, тогда t= корень из ( 2h/g ) = корень из 2*20/10= корень из 4 = 2

2)S=v0t=25*2=50 м

Ответ: 50 м

Answer 2

Calculation of the Range of Projectile Motion

To find the range of the projectile, we can use the equations of motion. The horizontal motion of the projectile is unaffected by gravity, so we can treat it as a constant velocity motion. The vertical motion is affected by gravity, so we can use the equations of motion to find the time of flight.

Given: - Initial height (h) = 20 m - Initial velocity (v0) = 25 m/s

To find the range (R) of the projectile, we need to find the time of flight (t) first.

Finding the Time of Flight

Using the equation of motion for vertical motion:

h = v0t - (1/2)gt^2

Where: - h is the initial height (20 m) - v0 is the initial vertical velocity (0 m/s, as the projectile is launched horizontally) - g is the acceleration due to gravity (9.8 m/s^2) - t is the time of flight

Rearranging the equation to solve for t:

t = sqrt(2h/g)

Substituting the given values:

t = sqrt(2 * 20 / 9.8) ≈ 2.02 s

Finding the Range

The range (R) of the projectile can be calculated using the equation:

R = v0 * t

Substituting the given values:

R = 25 * 2.02 ≈ 50.5 m

Therefore, the range of the projectile is approximately 50.5 meters.