Question

. Какую скорость приобретает автомобиль при торможении с ускорением 0,5 м /с2 через 10 с от начала торможения, если начальная скорость его была равна 36 км /ч?

Answer 1

1)36км/ч=10м/с

2)V=Vo-at

V=10-0.5*10=5м/с

Answer 2

s=a*tквадрат/2= 0.5*100/2=25

v=2s/v=25*2/10=5 

Answer 3

Calculation of the Deceleration:

To determine the speed acquired by a car during braking, we need to calculate the deceleration first. The deceleration is given as 0.5 m/s^2 in this case.

Conversion of Initial Speed:

The initial speed of the car is given as 36 km/h. To calculate the speed in m/s, we need to convert it. 1 km/h is equal to 0.2778 m/s Therefore, the initial speed of the car is: 36 km/h * 0.2778 m/s = 10 m/s.

Calculation of Final Speed:

To calculate the final speed acquired by the car during braking, we can use the following equation of motion: v = u + at, where: - v is the final speed, - u is the initial speed, - a is the deceleration, and - t is the time taken for braking.

In this case, the initial speed (u) is 10 m/s, the deceleration (a) is -0.5 m/s^2 (negative because it represents deceleration), and the time taken for braking (t) is 10 seconds.

Plugging in these values into the equation, we get: v = 10 m/s + (-0.5 m/s^2) * 10 s = 10 m/s - 5 m/s = 5 m/s.

Therefore, the final speed acquired by the car during braking is 5 m/s.

Please let me know if there's anything else I can help you with!