Question

Пассажир поезда, движущегося со скоростью 54 км/ч, заметил, что встречный поезд, состоящий из 12 вагонов, промелькнул за 10 с. Длина каждого вагона 24,5 м. Какова скорость встречного поезда?

Answer 1

 $V_{1} = \frac{54000}{3600} =15$ м/с
Т.к. поезд встречный, то скорость движения второго поезда относительно первого
$V = V_{1} + V_{2}$
Движение равномерное, значит.
$S = Vt$
$Nl = (V_{1} + V_{2})t$
$294 = 10(15 + V_{2})$
$V_{2} = 14,4$ м/с

Answer 2

Calculation of the Speed of the Oncoming Train

To calculate the speed of the oncoming train, we can use the formula:

Speed = Distance / Time

In this case, the distance covered by the oncoming train is equal to the length of all the 12 wagons, and the time taken is given as 10 seconds.

Let's calculate the distance covered by the oncoming train:

Distance = Number of Wagons * Length of Each Wagon

Given that there are 12 wagons and each wagon has a length of 24.5 meters, we can calculate the distance covered by the oncoming train:

Distance = 12 * 24.5 meters

Now, let's calculate the speed of the oncoming train using the formula mentioned above:

Speed = Distance / Time

Substituting the values, we get:

Speed = (12 * 24.5 meters) / 10 seconds

Calculating this, we find:

Speed = 29.4 meters per second

However, the speed is given in kilometers per hour, so we need to convert it. There are 1000 meters in a kilometer and 3600 seconds in an hour. Therefore, we can convert the speed from meters per second to kilometers per hour using the following conversion factor:

1 meter per second = (1 * 3600) / 1000 kilometers per hour

Let's calculate the speed of the oncoming train in kilometers per hour:

Speed = (29.4 meters per second) * (3600 / 1000) kilometers per hour

Calculating this, we find:

Speed = 105.84 kilometers per hour

Therefore, the speed of the oncoming train is approximately 105.84 kilometers per hour.

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