Question

шарик скатывается по желобу длиной 125 см с ускарением 1,6 м /с в квадрате.какова скорость шарика в конце желоба?начальная скорость шарика была равна 0

Answer 1

существует формула 2as=v^2-v0^2

т.к.v0=0 по условию то 2aS=v^2

v= 2as= корень из(2*1.6*1.25) = корень из 4 = 2 (м/с)

 

Answer 2

Calculation of the Ball's Speed at the End of the Chute

To calculate the speed of the ball at the end of the chute, we can use the equations of motion. Given the following information:

- Length of the chute (s): 125 cm - Acceleration (a): 1.6 m/s^2 - Initial velocity (u): 0 m/s

We can use the equation of motion:

v^2 = u^2 + 2as

where: - v is the final velocity - u is the initial velocity - a is the acceleration - s is the displacement

Plugging in the values, we have:

v^2 = 0^2 + 2 * 1.6 * 1.25

Simplifying the equation, we get:

v^2 = 4

Taking the square root of both sides, we find:

v = 2 m/s

Therefore, the speed of the ball at the end of the chute is 2 m/s.