Question

груз массой 0,1 кг привязвнный к нити длиной 1м,совершает колебания в вертикальной плоскости.чему равен момент силы тяжести груза относительно точки подвеса при отклонении нити от вертикали на угол 30 градусов

Answer 1

Fтяж=0,1*9,8=0,98 Н

Fшар=Fтяж*cos60=0.49 H

M=Fl=0.49*1=0.49 Нм

Answer 2

Calculation of the Moment of Gravity Force

To calculate the moment of the gravity force of a mass attached to a string, we need to consider the following information:

- Mass of the object (m): 0.1 kg - Length of the string (L): 1 m - Angle of deviation from the vertical (θ): 30 degrees

The moment of the gravity force (M) can be calculated using the formula:

M = m * g * L * sin(θ)

Where: - m is the mass of the object - g is the acceleration due to gravity (approximately 9.8 m/s^2) - L is the length of the string - θ is the angle of deviation from the vertical

Let's substitute the given values into the formula:

M = 0.1 kg * 9.8 m/s^2 * 1 m * sin(30 degrees)

Using a calculator, we can find the sine of 30 degrees, which is approximately 0.5. Substituting this value into the equation:

M = 0.1 kg * 9.8 m/s^2 * 1 m * 0.5

Simplifying the equation:

M = 0.49 Nm

Therefore, the moment of the gravity force of the mass, relative to the point of suspension, when the string is deviated from the vertical by an angle of 30 degrees, is approximately 0.49 Nm.