Question

20 балов ПОМОГИТЕ СРОЧНО Спортсмен бросил мяч с высоты м h=2 м и поймал его на той же высоте. Чему равен путь и модуль перемещения мяча? Ответы выразить в м м, округлив до целых. СРАЗУ ГОВОРЮ 0 НЕ ВЕРНО

Answer 1

Если имеется ввиду, что брошенный мяч отскочил от пола и вернулся в руку спортсмена, то:
l(путь)=2+2=4м
S(перемещение)=0м, т.к. мяч вернулся в ту же точку, где и был изначально.

Ответ: l=4м; S=0м

Answer 2

Calculation of the Path and Displacement of the Ball

To calculate the path and displacement of the ball, we need to consider the initial height from which the ball was thrown and the height at which it was caught.

Given: - Initial height (h) = 2 m - The ball was caught at the same height (2 m)

To calculate the path of the ball, we need to find the total distance traveled by the ball from the moment it was thrown until it was caught. Since the ball was caught at the same height it was thrown, the path of the ball is equal to twice the initial height.

Path of the ball = 2 * h = 2 * 2 = 4 m.

To calculate the displacement of the ball, we need to find the difference between the initial and final positions of the ball. In this case, since the ball was caught at the same height it was thrown, the displacement of the ball is zero.

Displacement of the ball = 0 m.

Therefore, the path of the ball is 4 meters and the displacement is 0 meters.

I hope this helps! Let me know if you have any further questions.