
Постройте изображение предмета в собирающей линзе для случаев d=3F, d<F


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Building an Image in a Converging Lens for d=3F, dWhen an object is placed within the focal point of a converging lens (d=3F, d1. Position of the Object:
- When the object is placed at a distance d=3F from the converging lens, it is located between the focal point and the optical center of the lens.
2. Ray Diagram:
- To visualize the formation of the image, we can use a ray diagram.
- The first ray is drawn parallel to the principal axis, and after refraction, it passes through the focal point on the opposite side of the lens.
- The second ray is drawn through the optical center of the lens, and it continues in the same direction without any deviation.
3. Image Formation:
- The two refracted rays appear to diverge from a point behind the lens, thus forming a virtual image.
- This virtual image is located on the same side of the lens as the object, and it is larger, upright, and virtual.
In summary, when an object is placed at a distance d=3F from a converging lens, the resulting image is virtual, upright, and larger than the object. This can be visualized through a ray diagram showing the paths of the refracted rays.
If you have further questions or need additional details, feel free to ask!
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When an object is placed within the focal point of a converging lens (d=3F, d 1. Position of the Object:
- When the object is placed at a distance d=3F from the converging lens, it is located between the focal point and the optical center of the lens. 2. Ray Diagram:
- To visualize the formation of the image, we can use a ray diagram.
- The first ray is drawn parallel to the principal axis, and after refraction, it passes through the focal point on the opposite side of the lens.
- The second ray is drawn through the optical center of the lens, and it continues in the same direction without any deviation. 3. Image Formation:
- The two refracted rays appear to diverge from a point behind the lens, thus forming a virtual image.
- This virtual image is located on the same side of the lens as the object, and it is larger, upright, and virtual. In summary, when an object is placed at a distance d=3F from a converging lens, the resulting image is virtual, upright, and larger than the object. This can be visualized through a ray diagram showing the paths of the refracted rays. If you have further questions or need additional details, feel free to ask!
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