Question

Наибольшая длина волны света, при которой наблюдается фотоэффект для калия, равна = 620 нм. Определите работу выхода (Авых) электронов из калия. Определите максимальную скорость фотоэлектронов (v), вырываемых из калия излучением с частотой = 9,1•1014 Гц.

Answer 1

Решение во вложении:

Answer 2

Determining the Work Function (Φ) of Potassium

The work function (Φ) of a material refers to the minimum amount of energy required to remove an electron from the surface of the material. In the case of potassium (K), we can determine the work function using the given information about the maximum wavelength of light that exhibits the photoelectric effect.

According to the question, the maximum wavelength of light that exhibits the photoelectric effect for potassium is 620 nm. To determine the work function, we can use the equation:

Φ = hc/λ

Where: - Φ is the work function - h is Planck's constant (6.626 x 10^-34 J·s) - c is the speed of light (3.00 x 10^8 m/s) - λ is the wavelength of light

Substituting the given values into the equation, we can calculate the work function of potassium:

Φ = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (620 x 10^-9 m)

Calculating this expression gives us the value of the work function (Φ) for potassium.

Determining the Maximum Velocity (v) of Photoelectrons

To determine the maximum velocity (v) of the photoelectrons emitted from potassium, we can use the equation:

E = hv = 1/2 mv^2 + Φ

Where: - E is the energy of a photon - h is Planck's constant (6.626 x 10^-34 J·s) - v is the velocity of the photoelectron - m is the mass of the photoelectron - Φ is the work function

Since we know the frequency (f) of the incident radiation, we can use the equation:

E = hf

Substituting the given frequency (9.1 x 10^14 Hz) into the equation, we can calculate the energy of a photon.

Next, we can rearrange the equation to solve for the maximum velocity (v):

v = sqrt(2(E - Φ) / m)

Substituting the calculated energy of a photon and the previously determined work function (Φ) into the equation, we can calculate the maximum velocity (v) of the photoelectrons emitted from potassium.

Please note that the mass of the photoelectron (m) is approximately 9.11 x 10^-31 kg.

Let's calculate the work function (Φ) and the maximum velocity (v) using the given values.