Question

Какова напряженность электрического поля, создаваемого двумя зарчдами 6 нКл и 20 нКл в точке,находящейся между зарядами на расстоянии 0.03 м от первогозаряда на линии,соединяющей заряды?

Answer 1

Запишем напряженность для каждого зарядаr1=0.03 мE=9*10^9 /2 * (6*10^-9/(0.03)^2 - 20*10^-9/(0.02)^2  )= -195000 B = -195 кВE1=kq1 / ε(r1)^2Ответ 195000 B = 195 кВПо 

Answer 2

Calculation of Electric Field Intensity

To calculate the electric field intensity at a point between two charges, we can use Coulomb's law. Coulomb's law states that the electric field intensity at a point due to a point charge is directly proportional to the magnitude of the charge and inversely proportional to the square of the distance between the point charge and the point where the electric field is being measured.

The formula for the electric field intensity (E) due to a point charge is given by:

E = k * (Q / r^2)

Where: - E is the electric field intensity - k is the electrostatic constant (k = 9 x 10^9 Nm^2/C^2) - Q is the magnitude of the charge - r is the distance between the point charge and the point where the electric field is being measured

In this case, we have two charges: 6 nC and 20 nC. The distance between the point charges is 0.03 m.

Let's calculate the electric field intensity at the point between the charges.

For the first charge (Q1 = 6 nC) at a distance of 0.03 m: E1 = (9 x 10^9 Nm^2/C^2) * (6 x 10^-9 C) / (0.03 m)^2

For the second charge (Q2 = 20 nC) at a distance of 0.03 m: E2 = (9 x 10^9 Nm^2/C^2) * (20 x 10^-9 C) / (0.03 m)^2

Now, let's calculate the total electric field intensity at the point between the charges by adding the individual electric field intensities:

E_total = E1 + E2

Please note that the above calculations are based on the assumption that the charges are point charges and the electric field is being measured at a point on the line connecting the charges.

Let me calculate the values for you.