Question

101. Определите начальную температуру (в кельвинах) олова массой 0,6 кг, если при погружении его в воду массой 3 кг

Answer 1

Теплоемкость олова = 218
Теплоемкость воды = 4200
Количество теплоты, полученное водой Q= c*m*(t-t0) Q= 4200*3*(302-300)= 25 200 Дж
Оно равно количеству теплоты, отданному оловом, тогда

Q=c*m*(t0-t) => t0-t=Q\c*m => t0=Q\c*m+t
В условии задачи неявно дали понять, что конечная температура олова=конечной температуре воды=302 К. Тогда t0= (25 200\218*0,6)+302 = 192+302= 495 K

Answer 2

Calculating the Initial Temperature of Lead

To calculate the initial temperature of lead when it is submerged in water, we can use the formula for thermal equilibrium:

Initial temperature of lead (in Kelvin) = Final temperature of the system - (mass of water * specific heat capacity of water * change in temperature of water) / (mass of lead * specific heat capacity of lead)

Given: - Mass of lead (m_lead) = 0.6 kg - Mass of water (m_water) = 3 kg - Specific heat capacity of water (c_water) = 4186 J/kg*K - Specific heat capacity of lead (c_lead) = 128 J/kg*K - Final temperature of the system (T_final) = Temperature at thermal equilibrium

We need to find the initial temperature of lead.

Calculation

Using the formula mentioned above, we can calculate the initial temperature of lead:

T_initial = T_final - (m_water * c_water * (T_final - T_initial)) / (m_lead * c_lead)

Substituting the Given Values

Substituting the given values into the formula:

T_initial = T_final - (3 * 4186 * (T_final - T_initial)) / (0.6 * 128)

Solving for T_initial

We can solve for T_initial using the given equation. This involves rearranging the equation and solving for T_initial.

I'll calculate the value of T_initial using the given equation.