Question

Срочно нужна помощь. Запись полная. Вычислите, во сколько раз нужно повысить концентрацию вещества В в системе А (г) + 3В (г) → 2С (г), чтобы скорость прямой реакции возросла в 125 раз. Заранее спасибо

Answer 1

Решение данной задачи смотри в приложении

Answer 2

Calculation of Concentration Increase in Reaction System

To calculate the concentration increase required in substance B in system A (g) + 3B (g) → 2C (g) in order to increase the rate of the forward reaction by 125 times, we need to consider the stoichiometry of the reaction and the rate equation.

The stoichiometry of the reaction tells us that for every 3 moles of B that react, 2 moles of C are produced. Therefore, the rate of the forward reaction can be expressed as:

Rate = k[B]^3

Where [B] represents the concentration of substance B and k is the rate constant.

To increase the rate of the forward reaction by 125 times, we can set up the following equation:

125 * Rate = k * (x[B])^3

Where x represents the concentration increase in substance B.

To solve for x, we can rearrange the equation as follows:

x[B] = (125 * Rate / k)^(1/3)

Therefore, the concentration of substance B needs to be increased by a factor of (125 * Rate / k)^(1/3) in order to increase the rate of the forward reaction by 125 times.

Please note that the specific values of the rate constant and initial concentration of substance B are not provided in the question, so we cannot calculate the exact concentration increase without this information.