Question

Під дією якої сили в стержні виникає напруга 15×10(7)Па. Площа перерізу стержня 25×10(-6) м(2)?

Answer 1

Решение. P1+P2=0; Wk=(P1^2)/(2*m1)+(P2^2)/(2*m2); P2=-P1; Wk=P1^2*(1/(2*m1)+1/(2*m2)); P1^2=Wk/(1/(2*m1)+1/(2*m2))); Ek1=(P1^2)/(2*m1); Ek2=(P2^2)/(2*m2); P1^2=2,4*10^-36;
Ek1=(2,4*10^-36)/(10^-25)=2,4*10^-11; Ek2=(2,4*10^-36)/(3*10^-25)=0,8*10^-11;

Answer 2

Calculating Stress in a Rod

To calculate the stress in a rod, we can use the formula:

Stress (σ) = Force (F) / Area (A)

Given: Force (F) = ? Area (A) = 25×10^(-6) m^2 Stress (σ) = 15×10^7 Pa

Using the formula, we can solve for the force (F):

Force (F) = Stress (σ) × Area (A)

Substituting the given values: Force (F) = 15×10^7 Pa × 25×10^(-6) m^2

Calculating the force: Force (F) = 375 N

So, under the action of a force of 375 N, the stress of 15×10^7 Pa arises in the rod.