Question

Каков период колебаний груза массой 0,4 кг, подвешенного на пружине жёсткостью 400 Н/м?

Answer 1

Т=2п*корень из m/k=2*3,14* корень из (0,4/400)=0,2 с

Answer 2

Period of Oscillation for a Mass on a Spring

To calculate the period of oscillation for a mass on a spring, we can use the formula:

T = 2π√(m/k)

Where: - T = period of oscillation - m = mass of the object (in kg) - k = spring constant (in N/m)

Given: - m = 0.4 kg - k = 400 N/m

Calculation

Using the given values, we can calculate the period of oscillation:

T = 2π√(0.4/400) T = 2π√(0.001) T = 2π * 0.0316 T ≈ 0.1989 seconds

So, the period of oscillation for a mass of 0.4 kg on a spring with a stiffness of 400 N/m is approximately 0.1989 seconds.