
Полное решение плиз Время подъема грузового лифта на высоту 47 м состовляет 1,5 минуты. С какой
мощностью работает его двигатель, если поднимается груз 3,2 кг? 2) Какую бес полезную работу совершает двигатель насоса, если его КПД 90% а на подъем воды из колодца на поверхность требуется 0,5 кДж работы?

Ответы на вопрос




Calculation of the Power of the Elevator Motor
To calculate the power of the elevator motor, we can use the formula:
Power = Work / Time
Given: - Height = 47 m - Time = 1.5 minutes = 1.5 * 60 seconds = 90 seconds - Mass of the load = 3.2 kg
First, let's calculate the work done by the elevator motor using the formula:
Work = Force * Distance
The force can be calculated using Newton's second law of motion:
Force = Mass * Acceleration
Acceleration can be calculated using the formula:
Acceleration = Change in Velocity / Time
Since the elevator is moving vertically, the change in velocity is equal to the change in speed. The initial velocity is 0 m/s, and the final velocity can be calculated using the formula:
Final Velocity = Distance / Time
Substituting the values, we have:
Final Velocity = 47 m / 90 s
Now, we can calculate the acceleration:
Acceleration = (Final Velocity - Initial Velocity) / Time
Substituting the values, we have:
Acceleration = (Final Velocity - 0 m/s) / 90 s
Next, we can calculate the force:
Force = Mass * Acceleration
Substituting the values, we have:
Force = 3.2 kg * (Final Velocity - 0 m/s) / 90 s
Finally, we can calculate the work done by the elevator motor:
Work = Force * Distance
Substituting the values, we have:
Work = (3.2 kg * (Final Velocity - 0 m/s) / 90 s) * 47 m
Now, we can calculate the power of the elevator motor using the formula:
Power = Work / Time
Substituting the values, we have:
Power = [(3.2 kg * (Final Velocity - 0 m/s) / 90 s) * 47 m] / 90 s
Let's calculate the final velocity, acceleration, force, work, and power using the given values.
Calculation of the Power of the Pump Motor
To calculate the useful work done by the pump motor, we can use the formula:
Useful Work = Input Work * Efficiency
Given: - Input Work = 0.5 kJ - Efficiency = 90%
The useful work done by the pump motor is equal to the input work multiplied by the efficiency:
Useful Work = Input Work * Efficiency
Substituting the values, we have:
Useful Work = 0.5 kJ * 90%
Let's calculate the useful work done by the pump motor using the given values.
Note: The search results provided by You.com do not contain relevant information for the calculations. Therefore, I will proceed with the calculations based on the given information.


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