Question

В закрытом сосуде емкостью 20л находится углекислый газ при температуре Т=300 К. После того как часть газа выпустили, давление в сосуде понизилось на дельта p= 0.5 МПа. Определите массу выпущенного газа?

Answer 1

Дано V=20*10^-3   T=300К   ΔP=0,5MПа    M=44*10^-3 кг/моль

ΔP*V= Δm*R*T/M
Δm=ΔP*V*M/R*T=5*10^5*20*10^-3*44*10^-3/8,31*300=176*10^-3 кг

Answer 2

Calculation of the Mass of Released Gas

To determine the mass of the released gas, we can use the ideal gas law equation, which states that the pressure (P), volume (V), and temperature (T) of a gas are related by the equation PV = nRT, where n is the number of moles of gas and R is the ideal gas constant.

Given: - Volume of the closed vessel (V) = 20 L - Temperature (T) = 300 K - Change in pressure (ΔP) = 0.5 MPa

To find the mass of the released gas, we need to calculate the number of moles of gas released. We can rearrange the ideal gas law equation to solve for the number of moles (n):

n = (PV) / (RT)

Let's substitute the given values into the equation and calculate the number of moles of gas released.

n = ((P - ΔP)V) / (RT)

Substituting the values: - P = initial pressure - ΔP = change in pressure - V = volume - R = ideal gas constant - T = temperature

Since the initial pressure (P) is not given, we cannot calculate the exact number of moles of gas released. We need the initial pressure to determine the change in pressure (ΔP).

Unfortunately, the initial pressure (P) is not provided in the question or the search snippet. Therefore, we cannot calculate the mass of the released gas without this information.

Please provide the initial pressure (P) so that we can proceed with the calculation.