Question

Ученик массой 50 кг поднимается на 5 этаж за 2 мин .найдите мощьность ученика ,если высота одного этажа 3 метра,а первый этаж находится на уровне земли?

Answer 1

P = A/t,
A = m*g*H,
m = 50 кг, g=9,8 м/с^2, H = (5-1)*3 = 4*3 = 12 м,
t = 2*60 = 120 c
P = m*g*H/t = 50*9,8*12/120 (Вт) = 49 Вт

Answer 2

Calculating Power for the Student

To calculate the power of the student, we can use the formula:

Power = Work / Time

Where: - Work = Force × Distance - Force = Mass × Acceleration - Distance = Height of 5 floors - Time = 2 minutes

First, let's calculate the distance the student has traveled to reach the 5th floor.

Calculating Distance Traveled

The height of one floor is given as 3 meters, and the student has climbed 5 floors.

So, Distance = 3 meters/floor × 5 floors = 15 meters.

Calculating Work

The work done by the student is the force exerted to lift their body mass to a certain height.

The force required to lift the student is given by Force = Mass × Acceleration.

The acceleration due to gravity is approximately 9.81 m/s^2.

So, Force = 50 kg × 9.81 m/s^2 = 490.5 N.

Now, Work = Force × Distance = 490.5 N × 15 m = 7357.5 J.

Calculating Power

Now that we have the work done, we can calculate the power using the formula:

Power = Work / Time

Given that the time taken is 2 minutes, which is equal to 120 seconds, we can calculate the power.

So, Power = 7357.5 J / 120 s = 61.3125 watts.

Therefore, the power of the student is approximately 61.3125 watts.