Question

Определите силу натяжения троса лифта массой 500 кг в начале и в конце подъема,если ускорение в обоих случаях 2 м/с²

Answer 1

Второй законь Ньютона

F=ma

F=500*2=1000

F=1кН

Answer 2

Calculating Tension Force in the Lift Cable

To calculate the tension force in the lift cable at the beginning and end of the lift, we can use the formula:

Tension force (T) = (mass of the lift) * (acceleration due to gravity) + (mass of the lift) * (acceleration)

Given: - Mass of the lift (m) = 500 kg - Acceleration (a) = 2 m/s²

Tension Force at the Beginning of the Lift

Using the given values, we can calculate the tension force at the beginning of the lift:

T = (m * g) + (m * a)

Where: - m = 500 kg - g = acceleration due to gravity (approximately 9.81 m/s²)

Substitute the values: T = (500 kg * 9.81 m/s²) + (500 kg * 2 m/s²)

Calculating: T = (4905 N) + (1000 N) T = 5905 N

Therefore, the tension force at the beginning of the lift is approximately 5905 N.

Tension Force at the End of the Lift

Using the same formula, we can calculate the tension force at the end of the lift:

T = (m * g) + (m * a)

Substitute the values: T = (500 kg * 9.81 m/s²) + (500 kg * 2 m/s²)

Calculating: T = (4905 N) + (1000 N) T = 5905 N

Therefore, the tension force at the end of the lift is also approximately 5905 N.

This means that the tension force in the lift cable remains constant at approximately 5905 N throughout the lift.