Question

Какое кол-во теплоты необходимо для того,чтобы расплавить 1 тонну железа взятого при температуре 10 градусов Цельсия?

Answer 1

Дано:

m=1т==1000кг

t1=10гр.С

t2=1539гр.С

c=460Дж/кг гр.С

(лямбда)=27 * 10 в 4 степени Дж/кг

 

Решение: Q=Q1+Q2

Q1=cm(t2-t1)

Q2=(лямбда)m

Q1=460 * 1000 * (1539 -10) = 703340000Дж

Q2=27 * 10 в 4 степени * 1000 = 27000 * 10 в 4Дж

Q= 703340000 + 27000 * 10 в 4 = 70334 * 10 в 4 + 27000*10 в 4 = 97334 * 10 в 4Дж = 973340кДж 

 

Answer 2

Calculating the Heat Required to Melt 1 Ton of Iron

To calculate the amount of heat required to melt 1 ton of iron taken at a temperature of 10 degrees Celsius, we can use the formula:

Q = cmΔt

Where: - Q = heat required - c = specific heat capacity of iron - m = mass of the iron - Δt = change in temperature

First, we need to find the specific heat capacity of iron and the temperature change when melting.

Specific Heat Capacity of Iron and Temperature Change

The specific heat capacity of iron is approximately 450 J/kg°C.

The temperature change when melting iron is from its melting point to the initial temperature. The melting point of iron is approximately 1538°C.

Calculating the Heat Required

Using the formula Q = cmΔt, we can calculate the heat required to melt 1 ton (1000 kg) of iron from 10°C to its melting point:

Δt = 1538°C - 10°C = 1528°C

c = 450 J/kg°C

m = 1000 kg

Q = 1000 kg * 450 J/kg°C * 1528°C

Q ≈ 684,600,000 J

Therefore, the amount of heat required to melt 1 ton of iron taken at a temperature of 10 degrees Celsius is approximately 684,600,000 joules.