Question

В некоторой точке электростатического поля на заряд 6*10(-9) Кл действует сила, равная 3*10(-4) Н. Чему равна напряженность в этой точке?

Answer 1

Дано: q=6*10⁻⁹Кл, F=3*10⁻⁴Н
Найти: Е
Е=F/q
E= 3*10⁻⁴/6*10⁻⁹ =0,5*10⁵=50*10³ Н/Кл =50 кН/Кл

Answer 2

Calculation of Electric Field Intensity

To calculate the electric field intensity (also known as electric field strength or electric field magnitude) at a certain point in an electrostatic field, we can use the formula:

E = F / q

Where: - E is the electric field intensity, - F is the force acting on the charge at that point, and - q is the magnitude of the charge.

In this case, we are given that the force acting on a charge of 6 * 10^(-9) C is 3 * 10^(-4) N. We can use this information to calculate the electric field intensity at that point.

E = (3 * 10^(-4) N) / (6 * 10^(-9) C)

Calculating this expression gives us:

E = 5 * 10^4 N/C

Therefore, the electric field intensity at that point is 5 * 10^4 N/C.