Question

Найдите коэффициент жестокости стальной пружины,которая сжимается на 10 см под действием силы,равной 12 Н. Ооочень надо,помогите!

Answer 1

по закону Гука

 

 коэффициент жестокости  k=F/x= 12H/0.10м=120 Н/м

Answer 2

Согласно закону Гука:

F=kx;

k=F/x=12/0,1=120 H/м.

 

Ответ: 120 Н/м.

Answer 3

Calculation of the Spring Stiffness Coefficient

To find the spring stiffness coefficient, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:

F = k * x

Where: - F is the force applied to the spring (12 N in this case) - k is the spring stiffness coefficient (what we need to find) - x is the displacement of the spring (10 cm or 0.1 m in this case)

To find the value of k, we can rearrange the equation as follows:

k = F / x

Substituting the given values, we have:

k = 12 N / 0.1 m = 120 N/m

Therefore, the spring stiffness coefficient is 120 N/m.

Please note that the above calculation assumes that the spring follows Hooke's Law and behaves linearly within the given range of displacement.