Question

Какое количество теплоты необходимо затратить для плавления 20 кг алюминия при температуре 660°С?

Answer 1

Q=λm =390 кДж/кг · 20 кг= 7800 кДж=7.8 мДж

λ удельная теплота плавления - 390 кДж/кг

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Answer 2

Calculating the Heat Required to Melt 20 kg of Aluminum at 660°C

To calculate the amount of heat required to melt 20 kg of aluminum at 660°C, we can use the formula:

Q = L * m

Where: - Q = heat required - L = latent heat of fusion - m = mass of the substance

Given that the latent heat of fusion for aluminum is 39 * 10^4 J/kg, and the mass of aluminum is 20 kg, we can calculate the heat required as follows:

Q = 39 * 10^4 * 20 = 780 * 10^4 J = 7.8 * 10^6 J.

Therefore, the amount of heat required to melt 20 kg of aluminum at 660°C is 7.8 * 10^6 joules.

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