Question

Вертолёт, про летев в горизонтальном полёте по прямой 30 км, повернул под углом 90 и пролетел ещё 40 км. Найти путь и модуль перемещения вертолёта

Answer 1

 Путь: 30+40=70 км 
перемешение: 30*30 +40*40 = х*х х=50 км  может kakто помочь?

Answer 2

Problem Analysis

We are given that a helicopter flies horizontally in a straight line for 30 km and then turns at a 90-degree angle and flies an additional 40 km. We need to find the path and displacement of the helicopter.

Solution

To find the path of the helicopter, we can use the Pythagorean theorem. The path is the hypotenuse of a right triangle, with the two legs representing the distances flown in each direction.

Let's calculate the path using the Pythagorean theorem:

Path = √(30^2 + 40^2) = √(900 + 1600) = √2500 = 50 km

Therefore, the path of the helicopter is 50 km.

To find the displacement of the helicopter, we need to calculate the straight-line distance from the starting point to the ending point. The displacement is the shortest distance between the two points.

Since the helicopter flies in a straight line for 30 km and then turns at a 90-degree angle, the displacement is equal to the distance flown in the second leg of the journey, which is 40 km.

Therefore, the displacement of the helicopter is 40 km.

In summary: - The path of the helicopter is 50 km. - The displacement of the helicopter is 40 km.

Please let me know if you need any further clarification or assistance!