Question

Груз весом 40 Н равномерно поднимают при помощи подвижного блока под действием силы 50Н. Найдите КПД блока.

Answer 1

КПД=(mg\2F)*100%
Подвижный блок дает выигрыш в силе в 2 раз,то  перед силой будет коэффициент два
Тогда
КПД=
mg  -вес груза ,40 Н
F-сила подъёма, 50 Н
тогда
КПД=(40\2*50)*100%=(40\100)*100%=0,4*100&=40%
Ответ ---- (0,4 или 40%)

Answer 2

Calculation of Efficiency (КПД) of the Block

To calculate the efficiency (КПД) of the block, we need to know the work input and the work output of the block.

The work input (W_in) is given by the formula:

W_in = F_in * d_in

where F_in is the force applied and d_in is the distance over which the force is applied.

In this case, the force applied is 50 N.

The work output (W_out) is given by the formula:

W_out = F_out * d_out

where F_out is the force exerted by the block and d_out is the distance over which the force is exerted.

In this case, the force exerted by the block is 40 N.

To find the efficiency (КПД), we can use the formula:

Efficiency (КПД) = (W_out / W_in) * 100%

Now let's calculate the efficiency (КПД) of the block using the given values.

Calculation:

Given: Force applied (F_in) = 50 N Force exerted by the block (F_out) = 40 N

To calculate the efficiency (КПД), we need to find the distances over which the forces are applied and exerted. Unfortunately, the distances are not provided in the question. Without this information, it is not possible to calculate the efficiency (КПД) of the block accurately.

Please provide the distances over which the forces are applied and exerted so that we can calculate the efficiency (КПД) of the block accurately.