Question

Электрон движется в вакууме в однородном магнитном поле с индукцией 5 • 10-3 Тл; его скорость равна 1,0 • 104 км/с и направлена перпендикулярно к линиям магнитной индукции. Определите силу, действующую на электрон, и радиус окружности, по которой он движется.

Answer 1

F=q*v*B =1,6*10^(-19) кл  * 1,0 *10^7 м/с * 5 *10^(-3) Тл = 8*10^(-15) Н
F=q*v*B=ma=mv^2/R
q*B=mv/R
R=mv/(q*B)=1,0 *10^7 м/с/(1,7588*10^11 Кл/кг * 5 *10^(-3) Тл) = 0,01137139 м ~ 11,4 мм

Answer 2

Force Acting on the Electron:

The force acting on the electron can be determined using the formula: F = qvB. Where F is the force, q is the charge of the electron, v is the velocity of the electron, and B is the magnetic field strength.

Using the given values: - Charge of the electron, q = -1.6 x 10^-19 C - Velocity of the electron, v = 1.0 x 10^4 km/s = 1.0 x 10^7 m/s - Magnetic field strength, B = 5 x 10^-3 T

Substituting these values into the formula: F = (-1.6 x 10^-19 C) * (1.0 x 10^7 m/s) * (5 x 10^-3 T)

Calculating the force using the given values: F = -8 x 10^-12 N.

Radius of the Circular Path:

The radius of the circular path along which the electron moves can be determined using the formula: r = mv / (|q|B). Where r is the radius, m is the mass of the electron, v is the velocity of the electron, |q| is the magnitude of the charge of the electron, and B is the magnetic field strength.

The mass of the electron, m = 9.11 x 10^-31 kg.

Substituting the given values into the formula: r = (9.11 x 10^-31 kg) * (1.0 x 10^7 m/s) / (1.6 x 10^-19 C * 5 x 10^-3 T)

Calculating the radius using the given values: r ≈ 1.14 x 10^-2 m.

Therefore, the force acting on the electron is approximately -8 x 10^-12 N and the radius of the circular path along which it moves is approximately 1.14 x 10^-2 m.