Вопрос задан 02.08.2018 в 22:52. Предмет Физика. Спрашивает Сергеева Даша.

помогите.. Масса лодки с охотником в ней равна M=180кг. Из покоящейся лодки охотник делает выстрел

в горизонтальном направлении, вдоль лодки. Чему равна скорость отдачи лодки с охотником в ней, если масса пули m=0,01 кг, скорость равна v=900м/c?
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Отвечает Ефимкина Вика.

Импульс пули равен 0,01*900=9

 

а импульс лодки с охотником 9=180 X V значит V= 9:180=0.05 м/с.

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Recoil Velocity of the Boat

To calculate the recoil velocity of the boat with the hunter in it, we can use the principle of conservation of momentum. According to this principle, the total momentum before the shot is equal to the total momentum after the shot.

The total momentum before the shot is given by the product of the mass of the boat and the velocity of the boat, which is initially at rest:

Momentum before the shot = Mass of the boat × Velocity of the boat before the shot

The total momentum after the shot is given by the sum of the momentum of the boat and the momentum of the bullet:

Momentum after the shot = (Mass of the boat + Mass of the bullet) × Velocity of the boat after the shot

Since the bullet is shot in a horizontal direction along the boat, the velocity of the bullet is equal to the given velocity, v = 900 m/s.

Using the principle of conservation of momentum, we can equate the two expressions for momentum before and after the shot:

Mass of the boat × Velocity of the boat before the shot = (Mass of the boat + Mass of the bullet) × Velocity of the boat after the shot

Now we can solve this equation for the velocity of the boat after the shot, which is the recoil velocity we are looking for.

Let's substitute the given values into the equation and solve for the recoil velocity.

Mass of the boat (M) = 180 kg Mass of the bullet (m) = 0.01 kg Velocity of the bullet (v) = 900 m/s

180 kg × Velocity of the boat before the shot = (180 kg + 0.01 kg) × 900 m/s

Simplifying the equation:

180 kg × Velocity of the boat before the shot = 180.01 kg × 900 m/s

Dividing both sides of the equation by 180 kg:

Velocity of the boat before the shot = 900 m/s

Therefore, the velocity of the boat before the shot is 900 m/s.

Now we can substitute this value back into the equation to find the recoil velocity of the boat:

180 kg × 900 m/s = (180 kg + 0.01 kg) × Recoil velocity of the boat

Simplifying the equation:

162,000 kg·m/s = 180.01 kg × Recoil velocity of the boat

Dividing both sides of the equation by 180.01 kg:

Recoil velocity of the boat = 162,000 kg·m/s / 180.01 kg

Calculating the recoil velocity:

Recoil velocity of the boat ≈ 899.50 m/s

Therefore, the recoil velocity of the boat with the hunter in it is approximately 899.50 m/s.

Please note that the above calculation assumes an idealized scenario without considering factors such as friction, air resistance, and the boat's resistance to motion.

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