Question

Каков вес железа объемом 1см³ в чистой воде?Помогите плиз

Answer 1

Учитывая что m=p*V, a вес в воде
P=m1*g - m2*g=p1*V*g - p2*V*g=V*g*(p1-p2) ;
p1=7870 кг/м^3
p2=1000 кг/м^3
1см^3=0,000001 м^3
Р=0,000001*9,8*(7870-1000)=0,067 (Н)
Перевод в кг и м^3 для получения ответа в ньютонах (система СИ).

Answer 2

Iron Weight in Pure Water

The weight of iron with a volume of 1 cm³ in pure water can be calculated using the density of iron and the density of water.

Density of Iron: The density of iron is approximately 7.87 g/cm³.

Density of Water: The density of pure water is approximately 1 g/cm³.

Calculation

To find the weight of iron with a volume of 1 cm³ in pure water, we can use the formula:

Weight = Density × Volume

Substituting the values: Weight = 7.87 g/cm³ × 1 cm³ = 7.87 grams

Therefore, the weight of iron with a volume of 1 cm³ in pure water is approximately 7.87 grams.