Question

Визначте момент інерції кільця масою 200г радіусом 40см

Answer 1

M=0.2 кг    R=0.4 м   J=?
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J=m*R²=0.2*0.4²=0.032 кг*м²
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Answer 2

Moment of Inertia of a Ring

The moment of inertia of a ring can be calculated using the formula:

I = MR^2

Where: - I = moment of inertia - M = mass of the ring - R = radius of the ring

Calculation

Given: - Mass (M) = 200g = 0.2kg - Radius (R) = 40cm = 0.4m

Using the formula, we can calculate the moment of inertia (I) of the ring:

I = MR^2 I = 0.2kg * (0.4m)^2 I = 0.2kg * 0.16m^2 I = 0.032 kg m^2

So, the moment of inertia of the ring with a mass of 200g and a radius of 40cm is 0.032 kg m^2.