Question

1) Штангист поднимая штангу совершает работу 5 кДж за 2 секунды! 2) Мальчик массой 40 кг поднялся за 30 секунд на второй этаж дома расположенный на высоте 8 метров!!! Решите задачи пожалуйста))) По физике!!! Дам 15 баллов!!!!!

Answer 1

1) Р = А:t ; A = 5000 Дж, t = 2сек ; P = 5000/ 2 = 2500
2) 2. P = A:t ; A = mgh; P = mgh : t ; m = 40 кг, g =9.8 м/с во 2 ст. h = 8 м. P = 40*9.8*8:30 = 104,53

Answer 2

Task 1: Work done by a weightlifter

The work done by a weightlifter can be calculated using the formula:

Work = Force x Distance

In this case, the weightlifter is lifting a barbell, so the force can be calculated using the formula:

Force = Mass x Acceleration due to gravity

The distance is not given directly, but we can assume it is the vertical distance over which the weightlifter lifts the barbell.

Let's calculate the work done by the weightlifter:

Given: - Work = 5 kJ (kilojoules) - Time = 2 seconds

To calculate the force, we need to know the mass of the barbell. Unfortunately, the mass is not provided in the question. Therefore, we cannot calculate the exact force and, consequently, the work done by the weightlifter.

Without the mass of the barbell, we cannot provide a specific answer to this question.